C9050-042 exam dumps

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  • Exam Code: C9050-042
  • Exam Name: Developing with IBM Enterprise PL/I
  • No. of Questions: 140 Questions and Answers
  • Updated: Sep 10, 2026

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  • Total Questions: 140
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  • Total Questions: 140
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  • Total Questions: 140
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IBM C9050-042 Exam Syllabus Topics:

SectionObjectives
PL/I Language Fundamentals- Basic syntax and program structure
  • 1. Program compilation and execution flow
    • 2. Identifiers, keywords, and operators
      - Data types and declarations
      • 1. Arrays and structures
        • 2. Fixed and floating-point data types
          IBM Enterprise PL/I Features- Enterprise extensions
          • 1. Error handling and exception control
            • 2. Built-in functions and system interfaces
              File Handling and Data Management- Sequential and indexed file processing
              • 1. File input/output operations
                • 2. Record handling and buffers
                  Debugging and Optimization- Debugging techniques
                  • 1. Runtime diagnostics and tracing
                    • 2. Performance tuning basics
                      Program Control and Logic- Control statements
                      • 1. Conditional logic (IF, SELECT)
                        • 2. Loops and iteration

                          IBM Developing with IBM Enterprise PL/I Sample Questions:

                          A program reads a GSAM dataset sequentially, reads complementary information from DB2-
                          Databases and uses this information to update an IMS-Database, At the end of the program statistics
                          about how many records have been read and how many IMS-Segments have been updated should be
                          printed. The program should write checkpoints regularly and should be restartable. Which of the following
                          groups of information saved when the checkpoint is written will provide enough information to be able to
                          restart the program correctly?

                          • A. The number of records read from the GSAM dataset, the key of the last record read from the GSAM
                            dataset and the key of the last IMS segment updated.
                          • B. The number of records read from the GSAM dataset and the number of IMS segmentschanged.
                          • C. The key of the last record read from the GSAM dataset and the key of the last IMS segment changed.
                          • D. The key of the last IMS segment changed and the number of segments changed.
                          Answer: B

                          Requirement:
                          The function LEAPYEAR evaluates a given 4-digit number and returns '1'B if it is a leap year, '0'B if it is
                          not. This function is supposed to work for the years 2004 to 2015.
                          Leap years occur every four years, except for years ending in 00 that are not divisible by 400. Which of
                          the following solutions meets the requirement and does NOT need to be changed if the requirement
                          changes to: The function is supposed to work for the years 1900 to 3000.

                          • A. LEAPYEAR: PROC(YEAR) RETURNS(BIT(1));
                            DCL YEAR PlC '9999';
                            DCL (MOD,VERIFY) BUILTIN;
                            SELECT;
                            WHEN (VERIFY(YEAR,'0l23456789') ^= 0) RETURN('0'B);
                            WHEN (MOD(YEAR,100) = 0)RETURN('0'B);
                            WHEN (MOD(YEAR,4) = 0)RETURN('1'B);
                            OTHERRETURN('0'B);
                            END;
                            END LEAPYEAR;
                          • B. LEAPYEAR:PROC(YEAR) RETURNS(BIT(1));
                            DCL YEAR PlC '9999';
                            DCL (MOD,VERIFY) BUILTIN;
                            SELECT;
                            WHEN (VERIFY(YEAR '0123456769') ^= 0) RETURN('0'B); WHEN (MOD(YEAR,100) = 0)
                            RETURN('0'B);
                            WHEN (MOD(YEAR,400) = 0) RETURN('1'B);
                            WHEN (MOD(YEAR,4) = 0) RETURN('1'B);
                            OTHERRETURN('0'B);
                            END;
                            END LEAPYEAR;
                          • C. LEAPYEAR: PROC(YEAR) RETURNS(BIT(1));
                            DCL YEAR PlC '9999';
                            DCL VERIFY BUILTIN;
                            IFVERIFY(YEAR,0123456789)^= 0 THEN RETURN('0'B);
                            SELECT(YEAR);
                            WHEN (2004) RETURN('1'B);
                            WHEN (2008) RETURN('1'B);
                            WHEN (2012) RETURN('1'B);
                            OTHER RETURN('0'B);
                            END;
                            END LEAPYEAR;
                          • D. LEAPYEAR:PROC(YEAR) RETURNS(BIT(1));
                            DCL YEAR PlC '9999';
                            DCL (MOD,VERIFY) BUILTIN;
                            SELECT;
                            WHEN (VERIFY(YEAR '0123456789') ^= 0) RETURN('0'B);
                            WHEN (MOD(YEAR,400) = 0) RETURN('l'B); WHEN (MOD(YEAR,100) = 0) RETURN('0'B);
                            WHEN (MOD(YEAR,4) = 0) RETURN('1'B); OTHER RETURN('0'B);
                            END;
                            END LEAPYEAR;
                          Answer: D

                          Which of the following structures will NOT contain padding bytes if the PL/I default for alignment is
                          applied?

                          • A. DCL 1 A, 2 B FLOAT DEC (16), 2 F FLOAT DEC (16), 2 C FIXED DEC (5,2), 2 E FIXED BIN (31), 2 D
                            CHAR (3);
                          • B. DCL 1 A, 2 E FIXED BIN (31), 2 C FIXED DEC (5,2), 2 B FLOAT DEC (16), 2 F FLOAT DEC (16), 2 D
                            CHAR (3);
                          • C. DCL 1 A, 2 B FLOAT DEC (16), 2 F FLOAT DEC (16), 2 E FIXED BIN (31), 2 C FIXED DEC (5,2), 2 D
                            CHAR (3);
                          • D. DCL 1 A, 2 B FLOAT DEC (16), 2 C FLOAT DEC (5,2), 2 D CHAR (3), 2 E FIXED BIN (31), 2 F FLOAT
                            DEC (16);
                          Answer: C

                          A compiler listing annotated with execution counts per statement helps identify all of the following
                          EXCEPT

                          • A. Opportunities for code optimization
                          • B. Unexecuted statements and procedures
                          • C. Potentially miscoded conditions in IFs, WHEREs, WHILEs, and UNTILs
                          • D. Calls to library routines
                          Answer: D

                          Requirement:
                          All the characters of the CHAR(3) variable X must be tested to be numeric. Which of the following
                          solutions meets the requirement and does not require essential structural modifications when the
                          requirement is changed to the following: The first character of the CHAR(3) variable X must be tested to
                          be uppercase alphabetic, while the two other characters must be tested to be numeric.

                          • A. DCL ALPHA CHAR(26) VALUE('ABCDEFGHIJKLMNOPQRSTUVWXYZ');
                            DCL NUM CHAR(10) VALUE('0123456789');
                            IF TRANSLATE(X,(26)'A'!I(10)'9'ALPHA!!NUM) = '999'
                            THEN ... ; /*NUMERIC*/
                          • B. DCL NUM CHAR(10) VALUE('0l 23456789');
                            IF VERIFY(X,NUM) = 0
                            THEN ... /*NUMERIC*/
                          • C. DCL Y PIC'999';
                            DCL SWITCH BIT(1) INIT('1'B);
                            ON CONVERSION BEGIN;
                            SWITCH =
                            ONSOURCE = '000';
                            END;
                            Y = X;
                            IF SWITCH
                            THEN ... ; /*NUMERIC*/
                          • D. IFX >= '000' & X <= '999'
                            THEN ... /*NUMERIC*/
                          Answer: A

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