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"Developing with IBM Enterprise PL/I", also known as C9050-042 exam, is a IBM Certification. With the complete collection of questions and answers, PrepAwayTest has assembled to take you through 140 Q&As to your C9050-042 Exam preparation. In the C9050-042 exam resources, you will cover every field and category in IBM Certified Application Developer Certification helping to ready you for your successful IBM Certification.
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1. Given the following code, what will happen?
DCL(K, L) FIXED DEC (1);
K= 1;
L = 2;
PUT SKIP LIST (12+K/L);
A) The output is 12.4999999999999.
B) The resulting value is 6.5.
C) The program ends abnormally at runtime.
D) The output is 12.5.
2. An online, non-conversational main program (for CICS or IMS) contains all of the logic for a one-screen
(MAP or FORMAT) application. Which of the following will NOT be required?
A) Code which does all necessary initializations
B) Code that opens all needed databases
C) Code for each situation
D) Code which determines the situation to be applied for the current program execution
3. A programmer has submitted the following declaration for review. What feedback should be provided to
the programmer?
DCL 1 A,
2 B DIM (1000) FIXED BIN (31) INIT (0),
2 C DIM (1000) FIXED BIN(15) INIT (0);
A) Discuss with the programmer how many elements of the arrays need to be initialized.
B) A is incorrectly initialized and the code must be changed.
C) The code is good as written.
D) The declaration of A should be changed because the current declaration contains padding bytes.
4. Which of the following is the most appropriate reason to explicitly use COMMIT or ROLLBACK?
A) The program abends.
B) An online program updates DB2 and IMS objects.
C) A batch program performs mass deletions where all deleted rows are independent from each other.
D) The program calls unknown subroutines.
5. Input to a SORT routine requires the starting position of each field to be sorted. Which of the following
calculates a value of 5 for field B?
DCL 1 S,
2 A CHAR(4),
2 B BIN FIXED(31);
A) POINTERDIFF(ADDR(S), ADDR(S.B)) + 1
B) POINTERDIFF(ADDR(S.B), ADDR(S))
C) POINTERDIFF(ADDR(S.B),ADDR(S)) + 1
D) POINTERDIFF(ADDR(S), ADDR(S.B))
Solutions:
| Question # 1 Answer: C | Question # 2 Answer: B | Question # 3 Answer: A | Question # 4 Answer: C | Question # 5 Answer: C |
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